Matematika

Pertanyaan

kak soal integral lagi
kak soal integral lagi

2 Jawaban

  • Materi integral trigonometri
    Gambar lampiran jawaban ShanedizzySukardi
  • 1•
    dcos (3t + π/4) = -3 sin (3t + π/4) dt
    sin (3t + π/4) dt = -1/3 dcos (3t + π/4)

    ∫2sin (3t + π/4) dt [π/3 ... 0]
    = 2.(-1/3) ∫dcos (3t + π/4)
    = -2/3 cos (3t + π/4)
    = -2/3 ( cos (3.π/3 + π/4) - cos (3.0 + π/4))
    = -2/3 ( coa (π + 1/4 π) - cos π/4)
    = -2/3 ( cos 225° - cos 45°)
    = -2/3 (-2 × cos 45°)
    = 4/3 × 1/2 √2
    = 2/3 √2


    2•
    dsin (4x - 3) = 4 cos (4x - 3) dx
    cos (4x - 2) dx = 1/4 dsin (4x - 3)

    ∫3 cos (4x - 4) dx [1...0]
    = 3 . (1/4) ∫dsin (4x - 3)
    = 3/4 sin (4x - 3)
    = 3/4 ( sin (4.1 - 3) - sin (4.0 - 3))
    = 3/4 (sin 1 - sin (-3))
    = 3/4 (sin 1 + sin 3)
    = 3/4 (sin (180°/3,14 + sin (3 180°/3,14)
    = 3/4 × 0,981
    = 0,736