Integral tentu .. Pliss dijawab , besok pagi dikumpul

Penyelesaian:

[tex] \int\limits^ \pi _ \frac{ \pi }{2} {(3 - 2sinx)} \, dx [/tex]
= [tex] \int\limits^ \pi _ \frac{ \pi }{2} {(3)dx - \int\limits^ \pi _ \frac{ \pi }{2} {(2sinx)} [/tex]
= 3x + 2cosx ] π->π/2
= (3π + 2cosπ) - (3(π/2) + 2cos(π/2))
= (3π -2) - (3π/2 + 0)
= 3π/2 - 2 - 3π/2
= -2