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Pertanyaan

1) Hitunglah PH larutan NaOH 0,1N
2)hitunglah PH larutan HCl 0,1N
3)Hitunglah PH larutan CH3COOH 0,1N

1 Jawaban

  • NaOH --> Na+ + OH-
    [OH-] = 0.1
    pOH = -log[OH-] = -log 10^-1 = 1
    pH = pKw - pOH = 14 - 1 =13

    2.
    HCl --> H+ +Cl-
    [H+] = 0.1
    pH = -log[H+] = -log10^-1 = 1

    3.
    CH3COOH <--> CH3COO- + H+
    K = [CH3COO-].[H+]/[CH3COOH]
    10^-5 = [H+]^2 / 10^-1
    [H+] = 10^-3

    pH = -log[H+] = -log10^-3 = 3

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