diketahui x=2,y=3,dan z=5 tentukan nilai perpangkatan berikut.

Materi : Eksponen

Pembahasan :
A.

-3x²y³z
= -3(2)²(3)³(5)
= -3(4)(27)(5)
= -1620

B.

(4x⁴y¯²)/(3z²)
= [4(2)⁴(3)¯²]/[3(5)²]
= [64 . 1/9]/[75]
= (64/9)/75
= 64/675