tolong dijawab beserta caranya..... pleaseee
Matematika
bungkoboy
Pertanyaan
tolong dijawab beserta caranya..... pleaseee
2 Jawaban
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1. Jawaban khominghoo
3^7 x 9^½ : ⅓^(3 - 2×)
= 3^7 x √9 : 3^-(3 - 2×)
= 3^(7+1) : 3^(2× -3)
= 3^(8 -2× +3)
= 3^( 11 - 2× ) -
2. Jawaban SadonoSukirno
^ tanda pangkat
3^7 × 9^½ = (⅓)^3-2x
3^7 × (3²)^½ = (3^-1)^3-2x
3^7 × 3^(2×½) = 3^(-1(3-2x))
3^7 × 3^1 = 3^(-3+2x)
3^(7+1) = 3^(2x-3)
3^8 = 3^(2x-3)
8 = 2x - 3
8 + 3 = 2x
11 = 2x
x = 11/2 = 5,5