carilah hasil integral (x^3 + 4x^2 - 3x)^7 (6x^2 + 6x -6) dx

Penyelesaian:

Misal: y = x³ + 4x² -3x

∫ (x³ + 4x² -3x)^7 (6x² + 16x - 6) dx

dy/dx = 3x² + 8x - 3
dx = dy/3x² + 8x -3

∫ (y)^7 (6x² + 16x - 6) dy/3x² + 8x -3
= 2 ∫ (y)^7 dy
= 2 . 1/8 . y^8 + c
= 1/4 . y^8 + c
= [tex] \frac{1}{4}(x^3 + 4x^2 - 3x)^8 + c [/tex]