Tentukan nilai r pada persamaan bentuk aljabar (2×+3y)(p×+qy)=rײ+23×y+12y²

(2×+3y)(p×+qy)=rײ+23×y+12y²
= 2x(px) + 2x(qy) + 3y(px) + 3y(qy)
= 2px² + 2qxy + 3pxy + 3qy²
= 2px² + (2q+3p)xy + 3qy²
》2px² = rx²
》(2q+3p)xy² = 23xy
》3qy² = 12y² 》3p = 12 》p = 4
》2px² = rx² 》2p = r 》2(4) = r 》r = 8