Matematika

Pertanyaan

banyaknya nilai x yang memenuhi persamaan sin (2x - Π/3) = 1/√3 dimana -Π/2 < x < Π/2

1 Jawaban

  • Interval : -π/2 < x < π/2 atau -90° < x < 90°

    sin (2x - π/3) = 1/√3
    sin (2x - π/3) = sin 35,26°
    2x - π/3 = 35,26°
    2x = 35,26° + (180°/3)
    x = 95,26°/2
    x = 47,63°

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