diketahui f(x) = 12x^{2} - 36x-48 dan f'(-1) = 19 dan F(1) = -26, fungsi f(x) = ...

f'(x) = integral dr (12x^2 - 36x - 48) dx
f'(x) = 4x^3 - 18x^2 - 48x + c

f'(-1) = 19,
4(-1) - 18(1) - 48(-1) + c = 19
c = -7

f'(x) = 4x^3 - 18x^2 - 48x - 7

f(x) = integral dr (4x^3 - 18x^2 - 48x - 7) dx
f(x) = x^4 - 6x^3 - 24x^2 - 7x + c

f(1) = -26,
1 - 6 - 24 - 7 + c = -26
c = -26 + 36 = 10

maka f(x) = x^4 - 6x^3 - 24x^2 - 7x + 10

Semoga membantu dan rajinlah belajar.