Matematika

Pertanyaan

3log x^5 +3log y = 142 3log x + 3log y=6 nilai x+y=

1 Jawaban

  • Bab Logaritma
    Matematika SMA KelasX

    ³log x⁵ + ³log y = 142
    ³log (x⁵y) = 142
    x⁵y = 3¹⁴²

    ³log x + ³log y = 6
    ³log (xy) = 6
    xy = 3⁶

    x⁵y = 3¹⁴²
    x⁴ (xy) = 3¹⁴²
    x⁴ = 3¹⁴² : 3⁶
    x = (3¹⁴²⁻⁶)^(1/4)
    x = 3^(136 / 4)
    x = 3³⁴

    xy = 3⁶
    y = 3⁶ : x
    y = 3⁶ : 3³⁴
    y = 3⁶⁻³⁴
    y = 3⁻²⁸

    x + y = 3³⁴ + 3⁻²⁸

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