diketahuiF(x) = 2x-4, F'(3)= -4 dan F(0)=5. NilaiF(3)=

F''(x)=2x-4
F'(x)= Int. 2x-4 dx
=x²-4x + C
F'(3)=3²-4(3)+C=-4
C=-1
F'(x)=x²-4x-1
F(x)=Int. x²-4x-1 dx
=⅓x³-2x²-x+C
F(0)=0-0-0+C=5
C=5
F(x)=⅓x³-2x²-x+5
Maka F(3)=⅓(3)³-2(3)²-3+5=-7
jadikan jawaban terbaik jika membantu ya :)