tolong bantu sekarang plisss

Penyelesaian:

[tex] \frac{2 \sqrt{6} }{ \sqrt{3} + \sqrt{2} } [/tex]
= [tex] \frac{2 \sqrt{6} }{ \sqrt{3} + \sqrt{2} } . \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } [/tex]  (kalikan dengan akar sekawan nya)
= [tex] \frac{2 \sqrt{18} - 2 \sqrt{12} }{3 - 2} [/tex]
= [tex]2 \sqrt{18} - 2 \sqrt{12} [/tex]
= [tex]2( \sqrt{18} - \sqrt{12}) [/tex] 
= [tex]2(3 \sqrt{2} - 2 \sqrt{3}) [/tex]  (A).

log 2 = a
log 3 = b
log 360 = ...?

log 360 = log(2.3.2.3.10)
= log 2 + log 3 + log 2 + log 3 + log 10
= a + b + a + b + 1
log 360 = 2a + 2b + 1 (D).