sin 2 x - ½ √3 = 0 untuk 0 ≤ x ≤ 3π/2
Matematika
yunissamaulidya
Pertanyaan
sin 2 x - ½ √3 = 0 untuk 0 ≤ x ≤ 3π/2
2 Jawaban
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1. Jawaban Anonyme
Bab Trigonometri
Matematika SMA Kelas X
sin 2x - 1/2 √3 = 0
sin 2x = 1/2 √3
2x = π/3
x = π/6
2x = 2π/3
x = π/3
2x = 7π/3
x = 7π/6
HP = { π/6, π/3, 7π/6 } -
2. Jawaban hendrisyafa
Sin 2x = ½√3
= sin 60
= sin 60/180 π
= sin ⅓π
2x = ⅓π + k.2π
x = ¹/6 π + k.π
k = 0, x = ¹/6 π
k = ¹/6, x = ⅓π
k = 1, x = 7/6 π
Hp { ¹/6π, ⅓π, 7/6 π }