Penyelesaian dari persmaan mutlak 3|x+4|=2|1-2x|

|3x+12|=|2-4×|
(3x+12)pngkt 2 = (2-4x)pngkt 2
(3x+12)pngkt2 - (2-4x)pngkt 2 =0
((3x+12)+(2-4x))((3x+12)-(2-4x)) =0
(3x+12+2-4x)(3x+12-2+4x)=0
(-x+14)(7x+10) =0
-x+14 =0 7x+10=0
-x=-14 7x=-10
x=14 x= -10/7

HP {14, -10/7}