hasil dari integral batas atas 0 batas bawah 1 x^2 (x^3 + 2)^5 dx...

misal :
u = x³ + 2
du/dx = 3x²
x² dx = 1/3 du

∫x² (x³ + 2)^5 dx [1...0]
= ∫u^5 . 1/3 du
= 1/3 . 1/6 u^6
= 1/18 (x³ + 2)^6
= 1/18 ((1³ + 2)^6 - (0 + 2)^6)
= 1/18 (3^6 - 2^6)
= 1/18 . 665
= 36 17/18