15 POINN CUY Tolong di jawab ya Besaran vektor jika Fy=....... FR=....... Fx=16 N ∅= 37° BESOK dikumpul. pliss jawab

dik :
Fx = 16N
teta : 37°
dit :
a. Fy?
b. FR?
jwb?
a. teta = Fy/Fx
tan 37° = Fy/16
3/4 = Fy/16
Fy = 16 × 3 /4
Fy = 48/4
Fy= 12N

b.Fr = √Fx² + Fy²
= √16² + 12²
= √256 + 144
FR = √400
Fr = 20N

VEKTOR
• penguraian vektor

Fx = 16 N
α = 37° → cos α = 4/5, sin α = 3/5
Fy = __?
Fr = __?

Komponen arah horizontal
Fx = Fr cos α
16 = Fr • 4/5
Fr = 16 × 5/4
Fr = 20 N ← jwb

Komponen arah vertikal
Fy = Fr sin α
Fy = 20 • 3/5
Fy = 12 N ← jwb